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11-07-2009, 12:00 AM
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Redshirt
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Join Date: Nov 2009
Posts: 1
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Basketball Team
9 basketball players are trying out to be on a newly formed basketball team. Of these players, 5 will be chosen for the team. If 6 of the players are guards and 3 of the players are forwards, how many different teams of 3 guards and 2 forwards can be chosen?
1. 23
2. 30
3. 42
4. 60
5. 126
OA to come
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11-13-2009, 07:37 PM
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Zag for Life
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Join Date: Feb 2007
Location: Pendo Country, Wa
Posts: 2,753
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None of the above?
Actually just trying to blow some life into this one.
Is this a trick question, a math question or a question in need of a poll? 
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"Begin by knowing you have already arrived" Bach
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11-13-2009, 10:16 PM
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Zag for Life
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Join Date: Feb 2007
Location: ....deep in the trees, with a 4 iron
Posts: 19,365
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clarkhopes made one post, has not tried to entice anyone to respond and has totally disappeared after this one post. he/she has also sig line of eiweißpulver is suspect he/she is a clever spammer or advertiser hoping that one and all will click on eiweißpulver for an answer that is not and will not be forthcoming...
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"You don't miss your water, till the well runs dry." - William Bell
Last edited by Bocco : 11-13-2009 at 10:51 PM.
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11-13-2009, 10:56 PM
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Zag for Life
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Join Date: Feb 2007
Location: Anchorage, Alaska
Posts: 5,776
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fwiw ... I got 22, though I totally could have missed a lineup ... so, I'd say a)23
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“If they give you ruled paper, write the other way." ~ Juan Ramon Jimenez
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11-13-2009, 11:05 PM
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Zag for Life
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Join Date: Jan 2008
Location: Kirkland, WA
Posts: 11,147
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The answer is 60.
With 3 Forwards, there are only 3 combinations of 2 forwards. 1 and 2, 1 and 3, 2 and 3. Let's call them A, B and C.
Of the 6 Guards, there are only 20 combinations of 3 Guards.
123 124 125 126
134 135 136
145 146
156
234 235 236
245 246
256
345 346
356
456
Combining the two, there are 20 combinations with Forward Group A, 20 with Group B and 20 with Group C.
Total = 60 combinations.
Sorry. I like numbers.  |
11-13-2009, 11:22 PM
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Bleeds GU Blue
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Join Date: Feb 2007
Location: The other Dublin
Posts: 830
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A basketball post in the Foo?
2012 must be coming early.
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 I reject your reality and substitute my own.
The Foo is strong with this one.
Zags
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11-13-2009, 11:40 PM
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Zag for Life
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Join Date: Feb 2007
Location: Anchorage, Alaska
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Quote:
Originally Posted by Zagineer
The answer is 60.
With 3 Forwards, there are only 3 combinations of 2 forwards. 1 and 2, 1 and 3, 2 and 3. Let's call them A, B and C.
Of the 6 Guards, there are only 20 combinations of 3 Guards.
123 124 125 126
134 135 136
145 146
156
234 235 236
245 246
256
345 346
356
456
Combining the two, there are 20 combinations with Forward Group A, 20 with Group B and 20 with Group C.
Total = 60 combinations.
Sorry. I like numbers. |
You are right of course ... I separated the guards from forwards and got 20 different guard combos, and the three forward combos, but added  instead of multiplying.
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“If they give you ruled paper, write the other way." ~ Juan Ramon Jimenez
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11-13-2009, 11:59 PM
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Zag for Life
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Join Date: Jan 2008
Location: Kirkland, WA
Posts: 11,147
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Quote:
Originally Posted by Akzag
You are right of course ... I separated the guards from forwards and got 20 different guard combos, and the three forward combos, but added instead of multiplying. |
No worries, Ak. Frankly, I am totally in awe at what you do with Bracketology.
And it is much appreciated and enjoyed by many of us.  |
11-14-2009, 01:06 AM
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Professional Zag Fan
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Join Date: Feb 2007
Location: Spokane
Posts: 558
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Quote:
Originally Posted by Zagineer
The answer is 60.
With 3 Forwards, there are only 3 combinations of 2 forwards. 1 and 2, 1 and 3, 2 and 3. Let's call them A, B and C.
Of the 6 Guards, there are only 20 combinations of 3 Guards.
123 124 125 126
134 135 136
145 146
156
234 235 236
245 246
256
345 346
356
456
Combining the two, there are 20 combinations with Forward Group A, 20 with Group B and 20 with Group C.
Total = 60 combinations.
Sorry. I like numbers. |
Without going through all the combinations, its (6!/(3!3!))*(3!/2!) = 60 using factorials.  |
11-14-2009, 02:03 AM
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Zag for Life
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Join Date: Jan 2008
Location: Kirkland, WA
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Thanks, zd. I haven't used factorials in over 30 years. They're kind of esoteric, so I thought I'd take the methodic long hand approach.
Good thing there weren't 86 Forwards and 96 Guards.  |
11-14-2009, 09:36 AM
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Zag for Life
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Join Date: Feb 2007
Location: Portland, OR
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I have absolutely no idea what the hell any of you are talking about. At no point in your rambling, incoherent responses were you even close to anything that could be considered a rational thought. Everyone on this board is now dumber for having read them. I award you no points, and may God have mercy on your soul.
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"...life is nothing if you're not obsessed."
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11-14-2009, 11:22 AM
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Moderator
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Location: Mostly The Foo
Posts: 22,788
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He shoots, he scores. . .
Quote:
Originally Posted by TheBeast
I have absolutely no idea what the hell any of you are talking about. At no point in your rambling, incoherent responses were you even close to anything that could be considered a rational thought. Everyone on this board is now dumber for having read them. I award you no points, and may God have mercy on your soul.
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__________________
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Fear is a clever thief, don't let him steal from you.
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11-14-2009, 05:06 PM
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Professional Zag Fan
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Join Date: Apr 2009
Location: Moscow, Idaho
Posts: 732
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Quote:
Originally Posted by clarkhopes
9 basketball players are trying out to be on a newly formed basketball team. Of these players, 5 will be chosen for the team. If 6 of the players are guards and 3 of the players are forwards, how many different teams of 3 guards and 2 forwards can be chosen?
1. 23
2. 30
3. 42
4. 60
5. 126
OA to come
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False -- There is no way to put a 2cm shaft through a 50mm hole without expanding the hole or shrinking the shaft.
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A man should look for what is, and not for what he thinks should be. ~Albert Einstein
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11-14-2009, 09:35 PM
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Zag for Life
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Join Date: Feb 2007
Location: Portland, OR
Posts: 3,133
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Quote:
Originally Posted by JohnnyGonzaga
False -- There is no way to put a 2cm shaft through a 50mm hole without expanding the hole or shrinking the shaft.
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If it don't fit, force it.
That's my motto.
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"...life is nothing if you're not obsessed."
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11-16-2009, 03:46 PM
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Professional Zag Fan
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Join Date: Apr 2009
Location: Moscow, Idaho
Posts: 732
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Quote:
Originally Posted by TheBeast
If it don't fit, force it.
That's my motto.
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I like it! She might not though... 
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A man should look for what is, and not for what he thinks should be. ~Albert Einstein
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11-16-2009, 03:55 PM
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Time Zone Challenged Board Greeter
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Join Date: Feb 2007
Location: St. Clair, MO
Posts: 3,222
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Quote:
Originally Posted by TheBeast
If it don't fit, force it.
That's my motto.
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LOOOOOOOOOOOOOOOOOOOOOOLLLLL
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"Allow myself to introduce...myself" WOOHOO
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11-16-2009, 04:48 PM
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Bleeds GU Blue
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Join Date: Feb 2008
Location: Take the steak off the grill!
Posts: 801
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Quote:
Originally Posted by TheBeast
If it don't fit, force it.
That's my motto.
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thats what she said. |
11-16-2009, 09:43 PM
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Zag for Life
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Join Date: Nov 2007
Location: Pleasure Ridge Park
Posts: 20,404
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gr####opper
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"Can't never could"
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11-16-2009, 10:24 PM
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Zag for Life
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Join Date: Feb 2007
Location: Tacoma WA
Posts: 7,014
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Quote:
Originally Posted by Pargo the Destroyer
thats what she said.
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Nice. Uber's heard that one before.
btw, Zagineer: Uber thinks you failed to take into account that for every 3 forwards one is likely to be a swing and that for every 6 guards two is likely to be a swing so really there are 6 guards, 3 forwards and 3 2/3s even though there are only 9 potential players. Figure that sh*t out.
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If you can't handle the confusion, stay out of the Foo!
Uber is still accepting neg rep and succumbing to The Man!
Yes Uber Can!
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11-17-2009, 12:29 AM
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Professional Zag Fan
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Join Date: Feb 2007
Location: Spokane
Posts: 558
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Quote:
Originally Posted by UberZagFan
Uber thinks you failed to take into account that for every 3 forwards one is likely to be a swing and that for every 6 guards two is likely to be a swing so really there are 6 guards, 3 forwards and 3 2/3s even though there are only 9 potential players. Figure that sh*t out. |
Haven't checked the math, but....
6 guards + one combo guard = 7 players for 3 guard positions, or (7 choose 3)
3 forwards + 2 combo forwards = 5 players for 2 forward positions, or (5 choose 2)
This accounts for all total combinations allowing these hybrid positions. Treating the selection of guards and selection of forwards as individual events gives the factorial form [(7!)/(4!3!)]*[(5!)/(3!2!)] = 350 combinations. |
Yesterday, 06:10 PM
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Zag for Life
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Join Date: Feb 2007
Location: Pendo Country, Wa
Posts: 2,753
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I'm sure glad I brought this back up to the top from an ignominious end of one post, but where the hell is Clarkhopes? That's what I want to know! 
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"Begin by knowing you have already arrived" Bach
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